x^2+√2Y=√3、y^2+√2x=√3,求x+y
来源:百度知道 编辑:UC知道 时间:2024/09/22 16:40:22
x^2+√2y=√3
y^2+√2x=√3
x+y. xy的值
y^2+√2x=√3
x+y. xy的值
解:x^2+√2y=√3
y^2+√2x=√3
即x^2-y^2+√2(y-x)=0
(x-y)(x+y-√2)=0
所以x=y或x+y=√2
又x^2+√2y+y^2+√2x=2√3,即
(x+y)^2-2xy+√2(x+y)=2√3,即
2-2xy+2=2√3
xy=2-√3
两式相减
(y+x)(y-x)-√2(y-x)=0
(y-x)(y+x-√2)=0
x=y或x+y=√2
x=y时,
方程z^2+√2z-√3=0判别式不等于0,x不等于y.
因此:x+y=-√2
xy=-√3
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